QUOTE (fredk @ May 31 2015, 03:35 PM)
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That's correct, for a very local eruption. As the plume gets larger, the Coriolis force will become important. The Coriolis force will cause a radial plume to pick up some rotation relative to Ceres, at least at higher latitudes. Especially near the equator, there will also be a vertical component to the Coriolis force (for approximately horizontal-directed plume components), which will be opposite for eastward and westward directed plume components. Also the vertical-directed part of the plume will be deflected westward. So it's conceivable that this could cause an east-west asymmetry.
My guess is that the dark deposit (if that's what it is) east of region 5 is much too close to the source for the Coriolis effects to produce such a large asymmetry.
Sigh. The reason I didn't mention Coriolis forces is because they're likely to be negligible (as you agree). A simple calculation of the Rossby number shows that inertial forces in any supposed plume (which, I might add, I don't think is an explanation for
anything on Ceres) will dominate over Coriolis forces.
The Coriolis parameter, f = 2(ω).sin(φ), where ω = 1.9234x10
-4 rad s
-1 and φ is the latitude.
For a plume at mid-latitudes (φ = 45°) involving particles erupted at, say, 250 m s
-1 over a length scale that appears from the images to be around 100 km, then the Rossby number is ~ 10
For Coriolis forces to become marginally important on these length scales, the eruption velocities would need to be nearer 30 m
-1 (about 70 mph).
It's worth adding that ballistic emplacement over a maximum distance of 100 km in a gravity field of 0.27 m s
-2 requires a muzzle velocity of about 165 m s
-1 (and yes, I'm assuming planetary curvature is insignificant).